Create a function that takes in year and months as input, then return what year it would be after n-months have elapsed.
afterNMonths(2020, 24) ➞ 2022
afterNMonths(1832, 2) ➞ 1832
afterNMonths(1444, 60) ➞ 1449Assume that adding 12 months will always increment the year by 1.