Given two lists smarr and bigarr, we say smlst is an ordered sublist of bigarr if all the elements of smarr can be found in bigarr, and in the same order.

Examples:

• [4, 3, 2] is an ordered subarray of [5, 4, 3, 2, 1].
• [5, 3, 1] is an ordered subarray of [5, 4, 3, 2, 1].
• [5, 3, 1] is not and ordered subarray of [1, 2, 3, 4, 5] since elements are not in the same - [1, 2, 3] is an ordered subarray of [3, 2, 1, 2, 3].

Write a function that, given lists smarr and bigarr, decides if smarr is an ordered sublist of bigarr.

Examples

is_ord_sub([4, 3, 2], [5, 4, 3, 2, 1]) ➞ true

is_ord_sub([5, 3, 1], [5, 4, 3, 2, 1]) ➞ true

is_ord_sub([5, 3, 1], [1, 2, 3, 4, 5]) ➞ false

is_ord_sub([1, 2, 3], [3, 2, 1, 2, 3]) ➞ true

Notes

Be careful of examples like the fourth example, where the elements of smarr appear multiple times in bigarr.