Write the regular expression that will match a string if there are no spaces right before the last ending punctuation ?. Use the character class \S in your expression.

Example

txt1 = "Can read a spray chart and a balance sheet. 1 part Executive, 1 part entrepreneur, 2 parts geek and 3 parts baseball coach. Too many parts?"
txt2 = "Can read a spray chart and a balance sheet. 1 part Executive, 1 part entrepreneur, 2 parts geek and 3 parts baseball coach. Too many parts ?"
pattern = "yourregularexpressionhere"

bool(re.search(pattern, txt1)) ➞ True
bool(re.search(pattern, txt2)) ➞ False

Notes

• Mark Gallion's Twitter bio is used for educational purposes only.
• To search for the character ? in RegEx, the pattern must include \?.
• You don't need to write a function, just the pattern.
• Do not remove import re from the code.
• Find more info on RegEx and character classes in Resources.
• You can find all the challenges of this series in my Basic RegEx collection.